Optimal. Leaf size=753 \[ \frac{c x \left (3 A c d \left (-11 a^2 e^4+6 a c d^2 e^2+c^2 d^4\right )-a \left (-7 a^2 e^4 (3 C d-B e)+2 a c d^2 e^2 (13 C d-19 B e)-c^2 d^4 (C d-3 B e)\right )\right )+4 a^2 e \left (a^2 C e^4-2 a c e^2 \left (4 C d^2-e (3 B d-A e)\right )+c^2 d^2 \left (3 C d^2-2 e (3 B d-5 A e)\right )\right )}{8 a^2 \left (a+c x^2\right ) \left (a e^2+c d^2\right )^4}-\frac{e^3 \log \left (a+c x^2\right ) \left (a^2 C e^4-a c e^2 \left (3 A e^2-9 B d e+13 C d^2\right )+c^2 d^2 \left (10 C d^2-3 e (5 B d-7 A e)\right )\right )}{2 \left (a e^2+c d^2\right )^5}+\frac{e^3 \log (d+e x) \left (a^2 C e^4-a c e^2 \left (3 A e^2-9 B d e+13 C d^2\right )+c^2 d^2 \left (10 C d^2-3 e (5 B d-7 A e)\right )\right )}{\left (a e^2+c d^2\right )^5}+\frac{\sqrt{c} \tan ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right ) \left (3 A c d \left (35 a^2 c d^2 e^4-35 a^3 e^6+7 a c^2 d^4 e^2+c^3 d^6\right )+a \left (-5 a^2 c d^2 e^4 (25 C d-27 B e)+15 a^3 e^6 (3 C d-B e)+a c^2 d^4 e^2 (23 C d-45 B e)+c^3 d^6 (C d-3 B e)\right )\right )}{8 a^{5/2} \left (a e^2+c d^2\right )^5}-\frac{a \left (B c d \left (c d^2-3 a e^2\right )-e (A c-a C) \left (3 c d^2-a e^2\right )\right )-c x \left (A c d \left (c d^2-3 a e^2\right )-a \left (c d^2 (C d-3 B e)-a e^2 (3 C d-B e)\right )\right )}{4 a \left (a+c x^2\right )^2 \left (a e^2+c d^2\right )^3}+\frac{e^3 \left (a e^2 (2 C d-B e)-c d \left (4 C d^2-e (5 B d-6 A e)\right )\right )}{(d+e x) \left (a e^2+c d^2\right )^4}-\frac{e^3 \left (A e^2-B d e+C d^2\right )}{2 (d+e x)^2 \left (a e^2+c d^2\right )^3} \]
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Rubi [A] time = 3.14256, antiderivative size = 753, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.185, Rules used = {1647, 1629, 635, 205, 260} \[ \frac{c x \left (3 A c d \left (-11 a^2 e^4+6 a c d^2 e^2+c^2 d^4\right )-a \left (-7 a^2 e^4 (3 C d-B e)+2 a c d^2 e^2 (13 C d-19 B e)-c^2 d^4 (C d-3 B e)\right )\right )+4 a^2 e \left (a^2 C e^4-2 a c e^2 \left (4 C d^2-e (3 B d-A e)\right )+c^2 \left (3 C d^4-2 d^2 e (3 B d-5 A e)\right )\right )}{8 a^2 \left (a+c x^2\right ) \left (a e^2+c d^2\right )^4}-\frac{e^3 \log \left (a+c x^2\right ) \left (a^2 C e^4-a c e^2 \left (3 A e^2-9 B d e+13 C d^2\right )+c^2 \left (10 C d^4-3 d^2 e (5 B d-7 A e)\right )\right )}{2 \left (a e^2+c d^2\right )^5}+\frac{e^3 \log (d+e x) \left (a^2 C e^4-a c e^2 \left (3 A e^2-9 B d e+13 C d^2\right )+c^2 \left (10 C d^4-3 d^2 e (5 B d-7 A e)\right )\right )}{\left (a e^2+c d^2\right )^5}+\frac{\sqrt{c} \tan ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right ) \left (3 A c d \left (35 a^2 c d^2 e^4-35 a^3 e^6+7 a c^2 d^4 e^2+c^3 d^6\right )+a \left (-5 a^2 c d^2 e^4 (25 C d-27 B e)+15 a^3 e^6 (3 C d-B e)+a c^2 d^4 e^2 (23 C d-45 B e)+c^3 d^6 (C d-3 B e)\right )\right )}{8 a^{5/2} \left (a e^2+c d^2\right )^5}-\frac{a \left (B c d \left (c d^2-3 a e^2\right )-e (A c-a C) \left (3 c d^2-a e^2\right )\right )-c x \left (A c d \left (c d^2-3 a e^2\right )-a \left (c d^2 (C d-3 B e)-a e^2 (3 C d-B e)\right )\right )}{4 a \left (a+c x^2\right )^2 \left (a e^2+c d^2\right )^3}-\frac{e^3 \left (-a e^2 (2 C d-B e)-c d e (5 B d-6 A e)+4 c C d^3\right )}{(d+e x) \left (a e^2+c d^2\right )^4}-\frac{e^3 \left (A e^2-B d e+C d^2\right )}{2 (d+e x)^2 \left (a e^2+c d^2\right )^3} \]
Antiderivative was successfully verified.
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Rule 1647
Rule 1629
Rule 635
Rule 205
Rule 260
Rubi steps
\begin{align*} \int \frac{A+B x+C x^2}{(d+e x)^3 \left (a+c x^2\right )^3} \, dx &=-\frac{a \left (B c d \left (c d^2-3 a e^2\right )-(A c-a C) e \left (3 c d^2-a e^2\right )\right )-c \left (A c d \left (c d^2-3 a e^2\right )-a \left (c d^2 (C d-3 B e)-a e^2 (3 C d-B e)\right )\right ) x}{4 a \left (c d^2+a e^2\right )^3 \left (a+c x^2\right )^2}-\frac{\int \frac{-\frac{c \left (A \left (3 c^3 d^6+15 a c^2 d^4 e^2+12 a^2 c d^2 e^4+4 a^3 e^6\right )+a c d^3 \left (c d^2 (C d-3 B e)-a e^2 (3 C d-B e)\right )\right )}{\left (c d^2+a e^2\right )^3}-\frac{c e \left (A c^2 d^3 \left (9 c d^2+5 a e^2\right )+a \left (4 a^2 B e^5-3 c^2 d^4 (3 C d-5 B e)-5 a c d^2 e^2 (C d-3 B e)\right )\right ) x}{\left (c d^2+a e^2\right )^3}-\frac{c e^2 \left (A c \left (9 c^2 d^4-15 a c d^2 e^2-4 a^2 e^4\right )+a \left (4 a^2 C e^4-c^2 d^3 (9 C d-23 B e)+3 a c d e^2 (5 C d+B e)\right )\right ) x^2}{\left (c d^2+a e^2\right )^3}-\frac{3 c^2 e^3 \left (A c d \left (c d^2-3 a e^2\right )-a \left (c d^2 (C d-3 B e)-a e^2 (3 C d-B e)\right )\right ) x^3}{\left (c d^2+a e^2\right )^3}}{(d+e x)^3 \left (a+c x^2\right )^2} \, dx}{4 a c}\\ &=-\frac{a \left (B c d \left (c d^2-3 a e^2\right )-(A c-a C) e \left (3 c d^2-a e^2\right )\right )-c \left (A c d \left (c d^2-3 a e^2\right )-a \left (c d^2 (C d-3 B e)-a e^2 (3 C d-B e)\right )\right ) x}{4 a \left (c d^2+a e^2\right )^3 \left (a+c x^2\right )^2}+\frac{4 a^2 e \left (a^2 C e^4+c^2 \left (3 C d^4-2 d^2 e (3 B d-5 A e)\right )-2 a c e^2 \left (4 C d^2-e (3 B d-A e)\right )\right )+c \left (3 A c d \left (c^2 d^4+6 a c d^2 e^2-11 a^2 e^4\right )-a \left (2 a c d^2 e^2 (13 C d-19 B e)-c^2 d^4 (C d-3 B e)-7 a^2 e^4 (3 C d-B e)\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^4 \left (a+c x^2\right )}+\frac{\int \frac{\frac{c^2 \left (A \left (3 c^4 d^8+18 a c^3 d^6 e^2+87 a^2 c^2 d^4 e^4+32 a^3 c d^2 e^6+8 a^4 e^8\right )+a c d^3 \left (2 a c d^2 e^2 (11 C d-21 B e)+c^2 d^4 (C d-3 B e)-9 a^2 e^4 (3 C d-B e)\right )\right )}{\left (c d^2+a e^2\right )^4}+\frac{c^2 e \left (3 A c^2 d^3 \left (3 c^2 d^4+18 a c d^2 e^2+31 a^2 e^4\right )+a \left (8 a^3 B e^7-a^2 c d^2 e^4 (65 C d-59 B e)+3 c^3 d^6 (C d-3 B e)-2 a c^2 d^4 e^2 (7 C d+3 B e)\right )\right ) x}{\left (c d^2+a e^2\right )^4}+\frac{c^2 e^2 \left (A c \left (9 c^3 d^6+54 a c^2 d^4 e^2-19 a^2 c d^2 e^4-16 a^3 e^6\right )+a \left (8 a^3 C e^6-a^2 c d e^4 (C d-27 B e)-6 a c^2 d^3 e^2 (9 C d-11 B e)+3 c^3 d^5 (C d-3 B e)\right )\right ) x^2}{\left (c d^2+a e^2\right )^4}+\frac{c^3 e^3 \left (3 A c d \left (c^2 d^4+6 a c d^2 e^2-11 a^2 e^4\right )-a \left (2 a c d^2 e^2 (13 C d-19 B e)-c^2 d^4 (C d-3 B e)-7 a^2 e^4 (3 C d-B e)\right )\right ) x^3}{\left (c d^2+a e^2\right )^4}}{(d+e x)^3 \left (a+c x^2\right )} \, dx}{8 a^2 c^2}\\ &=-\frac{a \left (B c d \left (c d^2-3 a e^2\right )-(A c-a C) e \left (3 c d^2-a e^2\right )\right )-c \left (A c d \left (c d^2-3 a e^2\right )-a \left (c d^2 (C d-3 B e)-a e^2 (3 C d-B e)\right )\right ) x}{4 a \left (c d^2+a e^2\right )^3 \left (a+c x^2\right )^2}+\frac{4 a^2 e \left (a^2 C e^4+c^2 \left (3 C d^4-2 d^2 e (3 B d-5 A e)\right )-2 a c e^2 \left (4 C d^2-e (3 B d-A e)\right )\right )+c \left (3 A c d \left (c^2 d^4+6 a c d^2 e^2-11 a^2 e^4\right )-a \left (2 a c d^2 e^2 (13 C d-19 B e)-c^2 d^4 (C d-3 B e)-7 a^2 e^4 (3 C d-B e)\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^4 \left (a+c x^2\right )}+\frac{\int \left (\frac{8 a^2 c^2 e^4 \left (C d^2-B d e+A e^2\right )}{\left (c d^2+a e^2\right )^3 (d+e x)^3}+\frac{8 a^2 c^2 e^4 \left (4 c C d^3-c d e (5 B d-6 A e)-a e^2 (2 C d-B e)\right )}{\left (c d^2+a e^2\right )^4 (d+e x)^2}+\frac{8 a^2 c^2 e^4 \left (a^2 C e^4-a c e^2 \left (13 C d^2-9 B d e+3 A e^2\right )+c^2 \left (10 C d^4-3 d^2 e (5 B d-7 A e)\right )\right )}{\left (c d^2+a e^2\right )^5 (d+e x)}+\frac{c^3 \left (3 A c d \left (c^3 d^6+7 a c^2 d^4 e^2+35 a^2 c d^2 e^4-35 a^3 e^6\right )+a \left (a c^2 d^4 e^2 (23 C d-45 B e)-5 a^2 c d^2 e^4 (25 C d-27 B e)+c^3 d^6 (C d-3 B e)+15 a^3 e^6 (3 C d-B e)\right )-8 a^2 e^3 \left (a^2 C e^4-a c e^2 \left (13 C d^2-9 B d e+3 A e^2\right )+c^2 \left (10 C d^4-3 d^2 e (5 B d-7 A e)\right )\right ) x\right )}{\left (c d^2+a e^2\right )^5 \left (a+c x^2\right )}\right ) \, dx}{8 a^2 c^2}\\ &=-\frac{e^3 \left (C d^2-B d e+A e^2\right )}{2 \left (c d^2+a e^2\right )^3 (d+e x)^2}-\frac{e^3 \left (4 c C d^3-c d e (5 B d-6 A e)-a e^2 (2 C d-B e)\right )}{\left (c d^2+a e^2\right )^4 (d+e x)}-\frac{a \left (B c d \left (c d^2-3 a e^2\right )-(A c-a C) e \left (3 c d^2-a e^2\right )\right )-c \left (A c d \left (c d^2-3 a e^2\right )-a \left (c d^2 (C d-3 B e)-a e^2 (3 C d-B e)\right )\right ) x}{4 a \left (c d^2+a e^2\right )^3 \left (a+c x^2\right )^2}+\frac{4 a^2 e \left (a^2 C e^4+c^2 \left (3 C d^4-2 d^2 e (3 B d-5 A e)\right )-2 a c e^2 \left (4 C d^2-e (3 B d-A e)\right )\right )+c \left (3 A c d \left (c^2 d^4+6 a c d^2 e^2-11 a^2 e^4\right )-a \left (2 a c d^2 e^2 (13 C d-19 B e)-c^2 d^4 (C d-3 B e)-7 a^2 e^4 (3 C d-B e)\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^4 \left (a+c x^2\right )}+\frac{e^3 \left (a^2 C e^4-a c e^2 \left (13 C d^2-9 B d e+3 A e^2\right )+c^2 \left (10 C d^4-3 d^2 e (5 B d-7 A e)\right )\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^5}+\frac{c \int \frac{3 A c d \left (c^3 d^6+7 a c^2 d^4 e^2+35 a^2 c d^2 e^4-35 a^3 e^6\right )+a \left (a c^2 d^4 e^2 (23 C d-45 B e)-5 a^2 c d^2 e^4 (25 C d-27 B e)+c^3 d^6 (C d-3 B e)+15 a^3 e^6 (3 C d-B e)\right )-8 a^2 e^3 \left (a^2 C e^4-a c e^2 \left (13 C d^2-9 B d e+3 A e^2\right )+c^2 \left (10 C d^4-3 d^2 e (5 B d-7 A e)\right )\right ) x}{a+c x^2} \, dx}{8 a^2 \left (c d^2+a e^2\right )^5}\\ &=-\frac{e^3 \left (C d^2-B d e+A e^2\right )}{2 \left (c d^2+a e^2\right )^3 (d+e x)^2}-\frac{e^3 \left (4 c C d^3-c d e (5 B d-6 A e)-a e^2 (2 C d-B e)\right )}{\left (c d^2+a e^2\right )^4 (d+e x)}-\frac{a \left (B c d \left (c d^2-3 a e^2\right )-(A c-a C) e \left (3 c d^2-a e^2\right )\right )-c \left (A c d \left (c d^2-3 a e^2\right )-a \left (c d^2 (C d-3 B e)-a e^2 (3 C d-B e)\right )\right ) x}{4 a \left (c d^2+a e^2\right )^3 \left (a+c x^2\right )^2}+\frac{4 a^2 e \left (a^2 C e^4+c^2 \left (3 C d^4-2 d^2 e (3 B d-5 A e)\right )-2 a c e^2 \left (4 C d^2-e (3 B d-A e)\right )\right )+c \left (3 A c d \left (c^2 d^4+6 a c d^2 e^2-11 a^2 e^4\right )-a \left (2 a c d^2 e^2 (13 C d-19 B e)-c^2 d^4 (C d-3 B e)-7 a^2 e^4 (3 C d-B e)\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^4 \left (a+c x^2\right )}+\frac{e^3 \left (a^2 C e^4-a c e^2 \left (13 C d^2-9 B d e+3 A e^2\right )+c^2 \left (10 C d^4-3 d^2 e (5 B d-7 A e)\right )\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^5}-\frac{\left (c e^3 \left (a^2 C e^4-a c e^2 \left (13 C d^2-9 B d e+3 A e^2\right )+c^2 \left (10 C d^4-3 d^2 e (5 B d-7 A e)\right )\right )\right ) \int \frac{x}{a+c x^2} \, dx}{\left (c d^2+a e^2\right )^5}+\frac{\left (c \left (3 A c d \left (c^3 d^6+7 a c^2 d^4 e^2+35 a^2 c d^2 e^4-35 a^3 e^6\right )+a \left (a c^2 d^4 e^2 (23 C d-45 B e)-5 a^2 c d^2 e^4 (25 C d-27 B e)+c^3 d^6 (C d-3 B e)+15 a^3 e^6 (3 C d-B e)\right )\right )\right ) \int \frac{1}{a+c x^2} \, dx}{8 a^2 \left (c d^2+a e^2\right )^5}\\ &=-\frac{e^3 \left (C d^2-B d e+A e^2\right )}{2 \left (c d^2+a e^2\right )^3 (d+e x)^2}-\frac{e^3 \left (4 c C d^3-c d e (5 B d-6 A e)-a e^2 (2 C d-B e)\right )}{\left (c d^2+a e^2\right )^4 (d+e x)}-\frac{a \left (B c d \left (c d^2-3 a e^2\right )-(A c-a C) e \left (3 c d^2-a e^2\right )\right )-c \left (A c d \left (c d^2-3 a e^2\right )-a \left (c d^2 (C d-3 B e)-a e^2 (3 C d-B e)\right )\right ) x}{4 a \left (c d^2+a e^2\right )^3 \left (a+c x^2\right )^2}+\frac{4 a^2 e \left (a^2 C e^4+c^2 \left (3 C d^4-2 d^2 e (3 B d-5 A e)\right )-2 a c e^2 \left (4 C d^2-e (3 B d-A e)\right )\right )+c \left (3 A c d \left (c^2 d^4+6 a c d^2 e^2-11 a^2 e^4\right )-a \left (2 a c d^2 e^2 (13 C d-19 B e)-c^2 d^4 (C d-3 B e)-7 a^2 e^4 (3 C d-B e)\right )\right ) x}{8 a^2 \left (c d^2+a e^2\right )^4 \left (a+c x^2\right )}+\frac{\sqrt{c} \left (3 A c d \left (c^3 d^6+7 a c^2 d^4 e^2+35 a^2 c d^2 e^4-35 a^3 e^6\right )+a \left (a c^2 d^4 e^2 (23 C d-45 B e)-5 a^2 c d^2 e^4 (25 C d-27 B e)+c^3 d^6 (C d-3 B e)+15 a^3 e^6 (3 C d-B e)\right )\right ) \tan ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right )}{8 a^{5/2} \left (c d^2+a e^2\right )^5}+\frac{e^3 \left (a^2 C e^4-a c e^2 \left (13 C d^2-9 B d e+3 A e^2\right )+c^2 \left (10 C d^4-3 d^2 e (5 B d-7 A e)\right )\right ) \log (d+e x)}{\left (c d^2+a e^2\right )^5}-\frac{e^3 \left (a^2 C e^4-a c e^2 \left (13 C d^2-9 B d e+3 A e^2\right )+c^2 \left (10 C d^4-3 d^2 e (5 B d-7 A e)\right )\right ) \log \left (a+c x^2\right )}{2 \left (c d^2+a e^2\right )^5}\\ \end{align*}
Mathematica [A] time = 1.22617, size = 672, normalized size = 0.89 \[ \frac{\frac{2 \left (a e^2+c d^2\right )^2 \left (-a^2 c e (e (A e-3 B d+B e x)+3 C d (d-e x))+a^3 C e^3-a c^2 d \left (3 A e (e x-d)+B d (d-3 e x)+C d^2 x\right )+A c^3 d^3 x\right )}{a \left (a+c x^2\right )^2}+\frac{\left (a e^2+c d^2\right ) \left (a^2 c^2 d e \left (e \left (40 A d e-33 A e^2 x-24 B d^2+38 B d e x\right )+2 C d^2 (6 d-13 e x)\right )+a^3 c e^3 (e (-8 A e+24 B d-7 B e x)+C d (21 e x-32 d))+4 a^4 C e^5+a c^3 d^3 x \left (3 e (6 A e-B d)+C d^2\right )+3 A c^4 d^5 x\right )}{a^2 \left (a+c x^2\right )}-4 \log \left (a+c x^2\right ) \left (a^2 C e^7+a c e^5 \left (-3 A e^2+9 B d e-13 C d^2\right )+c^2 d^2 e^3 \left (3 e (7 A e-5 B d)+10 C d^2\right )\right )+8 \log (d+e x) \left (a^2 C e^7+a c e^5 \left (-3 A e^2+9 B d e-13 C d^2\right )+c^2 d^2 e^3 \left (3 e (7 A e-5 B d)+10 C d^2\right )\right )+\frac{\sqrt{c} \tan ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right ) \left (3 A c d \left (35 a^2 c d^2 e^4-35 a^3 e^6+7 a c^2 d^4 e^2+c^3 d^6\right )+a \left (-5 a^2 c d^2 e^4 (25 C d-27 B e)-15 a^3 e^6 (B e-3 C d)+a c^2 d^4 e^2 (23 C d-45 B e)+c^3 d^6 (C d-3 B e)\right )\right )}{a^{5/2}}-\frac{8 e^3 \left (a e^2+c d^2\right ) \left (a e^2 (B e-2 C d)+c d e (6 A e-5 B d)+4 c C d^3\right )}{d+e x}-\frac{4 e^3 \left (a e^2+c d^2\right )^2 \left (e (A e-B d)+C d^2\right )}{(d+e x)^2}}{8 \left (a e^2+c d^2\right )^5} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.081, size = 2737, normalized size = 3.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.2198, size = 2068, normalized size = 2.75 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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